Answer
$5.64J$
Work Step by Step
Let us assume that the weight acts at the center of the book i.e. 2 cm=0.02m from base.
Work needed to stack all 6 books one after another $=mg\times(0.02+0.06+0.10+0.14+0.18+0.22)=0.8\times9.8\times0.72=5.64J$
College Physics (7th Edition)
by Wilson, Jerry D.; Buffa, Anthony J.; Lou, Bo
Published by
Pearson
ISBN 10:
0-32160-183-1
ISBN 13:
978-0-32160-183-4
Chapter 5 - Work and Energy - Learning Path Questions and Exercises - Exercises - Page 176: 39
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