Answer
$6J$
Work Step by Step
Work done = area under the curve = Area of first triangle + Area of second triangle + Area of rectangle = $\frac{1}{2}\times20N\times0.3m+\frac{1}{2}\times20N\times0.1m+20N\times0.1m=3+1+2=6J$
College Physics (7th Edition)
by Wilson, Jerry D.; Buffa, Anthony J.; Lou, Bo
Published by
Pearson
ISBN 10:
0-32160-183-1
ISBN 13:
978-0-32160-183-4
Chapter 5 - Work and Energy - Learning Path Questions and Exercises - Exercises - Page 175: 27
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