Answer
a) $250Hz$
b) $990Hz$
Work Step by Step
a) $L=250mH$, $X_{L}=400Ohm$
Inductive reactance = $X_{L}=2\times pi\times f\times L$
Thus, $f=\frac{400}{2\times3.14\times250\times10^{-3}}=250Hz$
b) Capacitive reactance = $\frac{1}{2\times 3.14\times f\times C}=\frac{1}{2\times 3.14\times 0.4\times10^{-6}\times400}=990Hz$