College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 1 - Measurement and Problem Solving - Learning Path Questions and Exercises - Exercises - Page 29: 31

Answer

a). 77.3 kg (rounded) b). 0.0733$\,m^{3}$ , 77.3 L

Work Step by Step

a). 1 kg= 2.2 lb 170 lb = $170 \times \frac{1}{2.2} \,kg= 77.3 \,kg$ (rounded) b). The person's density is same as that of water and its density is 1000 $kg/m^{3}$ Now, $Volume=\frac{Mass}{Density}$ $Volume=\frac{77.3 kg}{1000kg/m^{3}}=0.0773 m^{3}$ Also, $1 m^{3} = 1000 L$ So, $0.0773m^{3}=77.3L$ 1 L of water is equivalent to 1 kg mass. So the numerical value of volume would be same as the mass when expressed in L. So, it is convenient to express the volume in L.
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