College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 1 - Measurement and Problem Solving - Learning Path Questions and Exercises - Exercises - Page 29: 29

Answer

a). Option (1) has the greatest speed. b). 33.6 mi/hr.

Work Step by Step

a). (1)= 1 m/s (2) = 1 km/hr = 1000 m / 3600 s =$ \frac{1000}{3600} m/s$ $\approx 0.3 m/s $ (3) = 1 ft/s = 0.3048 m/s (4) = 1 mi/hr = 1.609 km/3600 s= $\frac{1.609\times 1000 m}{3600 s}\approx0.4 m/s$ Hence, option (1) is greatest. b). $15 m/s = 15 \times\frac{\frac{1mi}{1609}}{\frac{1 hr}{3600}}=15\times\frac{3600}{1609}=33.6 \,mi/hr$
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