College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 9 - Problems - Page 361: 21

Answer

The pressure on the whale at a depth of 2500 meters under the ocean surface is $2.52\times 10^7~Pa$

Work Step by Step

We can find the pressure at a depth of 2500 m under the ocean surface: $P_{abs} = P_{atm}+P_g$ $P_{abs} = P_{atm}+\rho~gh$ $P_{abs} = (1.01\times 10^5~N/m^2)+(1025~kg/m^3)(9.80~m/s^2)(2500~m)$ $P_{abs} = 2.52\times 10^7~N/m^2$ The pressure on the whale at a depth of 2500 meters under the ocean surface is $2.52\times 10^7~Pa$.
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