Answer
The pressure on a fish at a depth of 10 meters under the ocean surface is $2.01\times 10^5~Pa$
Work Step by Step
We can find the pressure at a depth of 10 m under the ocean surface:
$P_{abs} = P_{atm}+P_g$
$P_{abs} = P_{atm}+\rho~gh$
$P_{abs} = (1.01\times 10^5~N/m^2)+(1025~kg/m^3)(9.80~m/s^2)(10~m)$
$P_{abs} = 2.01\times 10^5~N/m^2$
The pressure on a fish at a depth of 10 meters under the ocean surface is $2.01\times 10^5~Pa$.
