Answer
$\tau = 98~N \cdot m$
Work Step by Step
We can find the torque due to the weight about the horizontal axis:
$\tau = r~F$
$\tau = r~mg$
$\tau = (1.0~m)(10.0~kg)(9.80~m/s^2)$
$\tau = 98~N \cdot m$
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