College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 6 - Problems - Page 229: 49

Answer

The comet's speed at perihelion is 55.1 km/s

Work Step by Step

We can use conservation of energy to find the comet's speed $v_p$ at perihelion: $\frac{1}{2}mv_p^2-\frac{G~M_s~m}{R_p} = \frac{1}{2}mv_a^2-\frac{G~M_s~m}{R_a}$ $v_p^2 = v_a^2+\frac{2G~M_s}{R_p} -\frac{2G~M_s}{R_a}$ $v_p^2 = v_a^2+2~G~M_s~(\frac{1}{R_p} -\frac{1}{R_a})$ $v_p = \sqrt{v_a^2+2~G~M_s~(\frac{1}{R_p} -\frac{1}{R_a})}$ $v_p = \sqrt{(1.00\times 10^4~m/s)^2+(2)(6.67\times 10^{-11}~m^3/kg~s^2)~(1.989\times 10^{30}~kg)~(\frac{1}{8.9\times 10^{10}~m} -\frac{1}{5.3\times 10^{12}~m})}$ $v_p = 5.51\times 10^4~m/s = 55.1~km/s$ The comet's speed at perihelion is 55.1 km/s.
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