College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 6 - Problems - Page 227: 9

Answer

The total work done on the box is $153~J$

Work Step by Step

We can find the total work done on the box: $Work = (66.0~N)(2.50~m)-(4.80~N)(2.50~m)$ $Work = 153~J$ The total work done on the box is $153~J$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.