Answer
The towrope does $12,960~J$ of work on the water-skier.
Work Step by Step
We can find the work done by the towrope on the water-skier:
$Work = F~d~cos~\theta$
$Work = (240~N)~(54~m)~cos~0^{\circ}$
$Work = 12,960~J$
The towrope does $12,960~J$ of work on the water-skier.
