College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 3 - Problems - Page 113: 32

Answer

The average velocity is $25.5~km/h$

Work Step by Step

We can find the east component of the displacement: $3.2~km+(4.8~km)~sin~15.0^{\circ}+3.2~km = 7.64~km$ We can find the north component of the displacement: $(4.8~km)~cos~15.0^{\circ} = 4.64~km$ We can find the magnitude of the displacement: $\sqrt{(7.64~km)^2+(4.64~km)^2} = 8.94~km$ We can find the average velocity $v_{av}$: $v_{av} = \frac{displacement}{time}$ $v_{av} = \frac{8.94~km}{0.35~h}$ $v_{av} = 25.5~km/h$ The average velocity is $25.5~km/h$
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