Answer
T= 400 N
Work Step by Step
The force of sign is$ F_{sign} $= 200 N. We assume we neglect the weight. The force exerted horizontally on the strut by the wall.
In order to evaluate the tension, we apply Newton's second law in Y-direction.
Σ Fy=T sin (30)- $ F_{sign} $ =0
Substituting from the given data, then we get
Σ Fy = T sin (30) - 200 N=0
Then we can evaluate the tension
T =$\frac{200N }{Sin30}$
= 400 N
