Answer
$I = 2.2\times 10^{-2}~A$
Work Step by Step
Since the positive charges and negative charges move in opposite directions, we can add the magnitudes of the flow of charges to find the total current.
$I = (1.6\times 10^{-19}~C)[(2)(3.8\times 10^{16})+6.2\times 10^{16}]~s^{-1}$
$I = 2.2\times 10^{-2}~A$
