College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 18 - Problems - Page 698: 1

Answer

$Q = 43,200~C$

Work Step by Step

We can find the total charge: $Q = A \times t$ $Q = (3.0~A)(4.0)(3600~s)$ $Q = (3.0~C/s)(4.0)(3600~s)$ $Q = 43,200~C$
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