Answer
The electric potential energy released is $1.25\times 10^9~J$
Work Step by Step
We can find the energy that is released:
$U = \frac{1}{2}~Q~V$
$U = \frac{1}{2}~(-25.0~C)(-1.00\times 10^8~V)$
$U = 1.25\times 10^9~J$
The electric potential energy released is $1.25\times 10^9~J$.
