Answer
$U = 2.4\times 10^{-6}~J$
Work Step by Step
We can find the energy stored in the capacitor:
$U = \frac{1}{2}~Q~V$
$U = \frac{1}{2}~(0.020\times 10^{-6}~C)(240~V)$
$U = 2.4\times 10^{-6}~J$
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