Answer
$Q = 6.12\times 10^{-4}~C$
Work Step by Step
We can find the magnitude of charge which must be removed from each plate:
$Q = C~V$
$Q = (10.2\times 10^{-6}~F)(60.0~V)$
$Q = 6.12\times 10^{-4}~C$
College Physics (4th Edition)
by Giambattista, Alan; Richardson, Betty; Richardson, Robert
Published by
McGraw-Hill Education
ISBN 10:
0073512141
ISBN 13:
978-0-07351-214-3
Chapter 17 - Problems - Page 655: 57
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
