Answer
$U = -1.125\times 10^{-5}~J$
Work Step by Step
We can find the electric potential energy:
$U = \frac{k~q_1~q_2}{r}$
$U = \frac{(9.0\times 10^9~N~m^2/C^2)(10.0\times 10^{-9}~C)(-10.0\times 10^{-9}~C)}{0.080~m}$
$U = -1.125\times 10^{-5}~J$
College Physics (4th Edition)
by Giambattista, Alan; Richardson, Betty; Richardson, Robert
Published by
McGraw-Hill Education
ISBN 10:
0073512141
ISBN 13:
978-0-07351-214-3
Chapter 17 - Problems - Page 652: 8
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