Answer
$\Delta U = 1.92\times 10^{-17}~J$
Work Step by Step
We can find the change in electric potential energy:
$\Delta U = q~\Delta V$
$\Delta U = q~(V_B-V_A)$
$\Delta U = (-1.6\times 10^{-19}~C)~[-360~V-(-240~V)]$
$\Delta U = 1.92\times 10^{-17}~J$
