College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 12 - Problems - Page 466: 73

Answer

The elapsed time between an emitted pulse and the return of its echo is $95.6~ms$

Work Step by Step

We can convert the depth to units of meters: $d = 40.0~fathoms\times \frac{1.83~m}{1~fathom} = 73.2~m$ We can use $v = 1533~m/s$ as the speed of sound in seawater. The pulse must travel to the bottom and return to the surface for a total distance of $2d$. We can find the required time: $t = \frac{2d}{v} = \frac{(2)(73.2~m)}{1533~m/s} = 0.0956~s = 95.6~ms$ The elapsed time between an emitted pulse and the return of its echo is $95.6~ms$.
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