Answer
A weight of $1284~N$ should be hung from the wire.
Work Step by Step
We can find the speed of sound in air:
$v = 331+0.6~T = 331+(0.6)(18.0^{\circ}C) = 341.8~m/s$
We can find the fundamental frequency of the tube:
$f = \frac{v}{\lambda}$
$f = \frac{v}{4L}$
$f = \frac{341.8~m/s}{(4)(1.50~m)}$
$f = 57.0~Hz$
We can find the required wave speed in the wire:
$v = \lambda~f$
$v = 2L~f$
$v = (2)(1.0~m)(57.0~Hz)$
$v = 114~m/s$
We can find the mass of 1.0-m of the wire:
$m = V~\rho$
$m = A~L~\rho$
$m = \pi~r^2~L~\rho$
$m = (\pi)~(2.00\times 10^{-3}~m)^2~(1.0~m)~(7860~kg/m^3)$
$m = 0.0988~kg$
We can find the required tension in the wire:
$\sqrt{\frac{F}{m/L}} = v$
$\sqrt{\frac{F~L}{m}} = v$
$\frac{F~L}{m} = v^2$
$F = \frac{m~v^2}{L}$
$F = \frac{(0.0988~kg)(114~m/s)^2}{1.0~m}$
$F = 1284~N$
A weight of $1284~N$ should be hung from the wire.
