Answer
$v_m^2 = a_m~A$
Work Step by Step
We can write an expression for $v_m^2$:
$v_m^2 = (A~\omega)^2 = A^2~\omega^2$
We can write an expression for $a_m$:
$a_m = A~\omega^2$
Then:
$v_m^2 = A^2~\omega^2 = (A~\omega^2)~A = a_m~A$
College Physics (4th Edition)
by Giambattista, Alan; Richardson, Betty; Richardson, Robert
Published by
McGraw-Hill Education
ISBN 10:
0073512141
ISBN 13:
978-0-07351-214-3
Chapter 10 - Problems - Page 399: 44
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