Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 6 - Exercises and Problems - Page 110: 46

Answer

$7.4\space m/s$

Work Step by Step

Please see the attache dimage first Let's apply the equation $F=ma$ to the bicycle when it has the maximum constant speed. $\angle 4.4^{\circ} \nearrow F=ma$ ; Let's plug known values into this equation. $F-14.5N-152gsin\theta\space N=0$ $F=(14.5+152\times9.8\times sin4.4^{\circ})\space N$ $F=128.8\space N$ Let's apply the equation $P=FV$ to the bicycle when it has the maximum constant speed. $P=FV$ ; Now plug known values into this equation $955\space kgm^{2}/s^{3}=128.8\space kgm/s^{2}\times V$ $7.4\space m/s=V$ Fastest speed of the bicycle = 7.4 m/s
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