Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 6 - Exercises and Problems - Page 110: 44

Answer

$6.9\times10^{-7}N/m$

Work Step by Step

Here we use the equation $W=\frac{1}{2}Kx^{2},$ Where W-work required to compress the DNA molecule, K- spring constant, x- the compressed distance of the DNA molecule $W=\frac{1}{2}Kx^{2}$ Let's plug known values into this equation. $6.92\times10^{-24}J=\frac{1}{2}K\times(4.48\space nm)^{2}$ $13.84\times10^{-24}J=K\times(4.48\times10^{-9}m)^{2}$ $\frac{0.69\times10^{-24}}{10^{-18}}N/m=K$ $K=6.9\times10^{-7}\space N/m$
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