Answer
$(a)\space 273.57\space N$
$(b)\space 143.6\space N$
Work Step by Step
(a) here we use Newton's second law of motion. let's apply equation $F=ma$ to the puck.
$\rightarrow F=ma$
Let's plug known values into this equation.
$F=162\times10^{-3}\space kg\times\frac{(86.8\space m/s-0)}{51.4\times10^{-3}\space s}$
$F=273.57\space N$
(b) We can write, centripetal force $(F_{1})=m(\frac{V^{2}}{r})$ for a circular motion.
Let's plug known values into this equation.
$F_{1}=162\times10^{-3}\space kg\times \frac{(86.8\space m/s)^{2}}{8.5\space m}$
$F_{1}=143.6\space N$
This is the force the puck received from the corner board for its circular motion. The corner board received the same force from the puck.
