Answer
$T_2=713.2K$
Work Step by Step
We find:
$(\frac{V_2}{V_1})^{\gamma-1}=\frac{T_1}{T_2}$
$(.118)^{.4}=\frac{303}{T_2}$
$T_2=713.2K$
Essential University Physics: Volume 1 (4th Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0-134-98855-8
ISBN 13:
978-0-13498-855-9
Chapter 18 - Exercises and Problems - Page 342: 45
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