Answer
Please see the work below.
Work Step by Step
(a) We know that
$W=-nC_v\Delta T$
$W=-n(\frac{3}{2}R)\Delta T$
We plug in the known values to obtain:
$-2500=-(1)\frac{3}{2}(8.314)\Delta T$
This simplifies to:
$\Delta T=200K$
(b) We know that
$W=-nC_v\Delta T$
$W=-n(\frac{5}{2}R)\Delta T$
We plug in the known values to obtain:
$-2500=-(1)\frac{5}{2}(8.314)\Delta T$
This simplifies to:
$\Delta T=120K$
