Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 17 - Exercises and Problems - Page 324: 18

Answer

Please see the work below.

Work Step by Step

We can find the required energy as $Q=mL$ We plug in the known values to obtain: $Q=(0.065)(334000)$ $Q=22000J$
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