Answer
Please see the work below.
Work Step by Step
We know that
$PV=nRT$
This can be rearranged as:
$P=\frac{nRT}{V}$
We plug in the known values to obtain:
$P=\frac{(3.5)(8.314)(273.15-150)}{0.002}$
$P=1.8\times 10^6Pa$
Essential University Physics: Volume 1 (4th Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0-134-98855-8
ISBN 13:
978-0-13498-855-9
Chapter 17 - Exercises and Problems - Page 324: 13
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