Answer
Yes, it could.
Work Step by Step
We first find the wind output per unit area:
$P=\frac{1}{2}\rho v^3 $
$ P = \frac{1}{2}(.3)(1.2)(12^2)=25.92 \ W$
We multiply this by the overall area:
$P_t=25.92\times \pi \times (\frac{95}{2})^2 \times 800=147 \ GW $
Thus, it could replace the power plant.
