Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 13 - Exercises and Problems - Page 246: 42

Answer

91.89 Hz

Work Step by Step

Here we use the equation $f=\frac{1}{2\pi}\sqrt {\frac{K}{m}}$ to find the resonant frequency. $f=\frac{1}{2\pi}\sqrt \frac{K}{m}$ ; Let's plug known values into this equation. $f=\frac{1}{2\pi}\sqrt {\frac{2.5\times10^{3}N/m}{7.5\times10^{-3}kg}}=91.89\space Hz$
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