Organic Chemistry, 5th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021553
ISBN 13: 978-0-07802-155-8

Chapter 1 - Section 1.2 - Lewis Structures - Problem - Page 15: 1.4

Answer

See image below:

Work Step by Step

1. Draw the central atoms, in these cases, put every atom that is not Hydrogen in the center. a. 2 C. b. C and N. c. C and Cl. 2. Put hydrogen around each central atom. 3. Count the electrons. a. 2x4 (C) + 6x1 (H) = 14 electrons. b. 1x4 (C) + 5x1 (H) + 1x5 (N) = 14 electrons. c. 1x4 (C) + 3x1 (H) + 1x7 (Cl) = 14 electrons. 4. Add the bonds between the atoms, and count how many electrons are not used. a. 14 - 7x2 = 0. b. 14 - 6x2 = 2. c. 14 - 4x2 = 6. 5. Add the remaining pairs of electrons to the appropriate atoms: b. Nitrogen only has 6 electrons, it needs 1 lone pair to reach 8. c. Chlorine only has 2 electrons, it needs 3 lone pairs to reach 8. - All the electrons were used, the Lewis Structure is valid.
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