Answer
$pH = 1.70$
This solution is acidic.
Work Step by Step
1. Since $HNO_3$ is a strong acid:
$Initial[HNO_3] = [H_3O^+] = 0.020M$
2. Calculate the pH Value.
$pH = -log[H_3O^+]$
$pH = -log( 0.020)$
$pH = 1.70$
$pH < 7$ at $25^{\circ}C$: Acidic solution.
