Answer
$[OH^-] = 1 \times 10^{- 3}M$
Work Step by Step
1. Calculate the pOH:
pH + pOH = 14
11 + pOH = 14
pOH = 3
2. Use this value to calculate the hydroxide concentration:
$[OH^-] = 10^{-pOH}$
$[OH^-] = 10^{- 3}$
$[OH^-] = 1 \times 10^{- 3}$
