General Chemistry: Principles and Modern Applications (10th Edition)

Published by Pearson Prentice Hal
ISBN 10: 0132064529
ISBN 13: 978-0-13206-452-1

Chapter 1 - Matter: Its Properties and Measurement - Exercises - Temperature Scales - Page 28: 44

Answer

The thermometer won't serve the purpose, since the minimal temperature range (234 $^{\circ}$F) is not visible on the thermometer

Work Step by Step

T($^{\circ}$C) = $\frac{5}{9}$ * [T($^{\circ}$F) - 32] T($^{\circ}$C) at 234 $^{\circ}$F: T($^{\circ}$C) = $\frac{5}{9}$ * [234 - 32] T($^{\circ}$C) = $\frac{5}{9}$ * [202] T($^{\circ}$C) = 112.2222222 $^{\circ}$C Rounding to 3 significant figures gives 112 $^{\circ}$C The minimal temperature range (234 $^{\circ}$F) is not visible on the thermometer, since 112 $^{\circ}$C is higher than 110 $^{\circ}$C. Therefore the thermometer won't serve the purpose.
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