Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 1 - Introduction: Matter and Measurement - Exercises - Page 37: 1.52f

Answer

0.140 g/mL

Work Step by Step

$\frac{8.75\ lb}{ft^3}\times\frac{453.59\ g}{1\ lb}\times\frac{1\ ft^3}{12^3\ in^3}\times\frac{1\ in^3}{2.54^3\ cm^3}\times\frac{1\ cm^3}{1mL}=0.140\ g/mL$
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