Answer
0.140 g/mL
Work Step by Step
$\frac{8.75\ lb}{ft^3}\times\frac{453.59\ g}{1\ lb}\times\frac{1\ ft^3}{12^3\ in^3}\times\frac{1\ in^3}{2.54^3\ cm^3}\times\frac{1\ cm^3}{1mL}=0.140\ g/mL$
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