Answer
Volume is $1.52\times10^4\ cm^3$
Uncertainty is $0.4\times10^3\ cm^3$
Work Step by Step
The volume is
$(24.8cm)^3=15,253cm^3=1.52\times10^4cm^3$
The uncertainty of the edge length is 0.2 cm, so actual edge length is between 24.6cm and 25cm.
The smallest possible volume is
$(24.6cm)^3=14,887cm^3=1.49\times10^4cm^3$
The largest possible volume is
$(25cm)^3=15,625cm^3=1.56\times10^4cm^3$
The difference between the boundary volumes is
$15,625cm^3-14,887cm^3=738cm^3$
The uncertainty is half the boundary range.
$738cm^3\div2=369cm^3=0.4\times10^3cm^3$
