Answer
(a) (1 x 23) + (1 x 16) + (1 x 1) = 40 u
(b) (39.098 x 2) + (1 x 12) + (16 x 3) = 138.196 u
(c) (3 x 40.078) + (30.974 x 2) + (16 x 8) = 310 u
Work Step by Step
We find, using the atomic masses on the periodic table:
(a) (1 x 23) + (1 x 16) + (1 x 1) = 40 u
(b) (39.098 x 2) + (1 x 12) + (16 x 3) = 138.196 u
(c) (3 x 40.078) + (30.974 x 2) + (16 x 8) = 310 u