Answer
(a) (39.098 x 2) + (1 x 32.06) + (16 x 4) = 174.26 u
(b) (107.87) + (1 x 14) + (16 x 3) = 169.87 u
(c) (1 x 14) + (1 x 4) + (35.45) = 53.45 u
Work Step by Step
We find, using the atomic masses on the periodic table:
(a) (39.098 x 2) + (1 x 32.06) + (16 x 4) = 174.26 u
(b) (107.87) + (1 x 14) + (16 x 3) = 169.87 u
(c) (1 x 14) + (1 x 4) + (35.45) = 53.45 u