Answer
$6.022 \times 10^{24}$ atoms of lead has the greater mass.
Work Step by Step
- $6.022 \times 10^{24}$ lead atoms:
$6.022 \times 10^{24} \times \frac{1 mol}{6.022 \times 10^{23}} = 10$ $moles$.
Since we are comparing the masses of 2 quantities of the same type of atom ($Pb$), the one with the higher number of moles has the greater mass.
10 moles $(Pb)$ > 1 mol $(Pb)$
Thus, $6.022 \times 10^{24}$ atoms of lead has the greater mass.
