Chemistry: The Molecular Science (5th Edition)

by Moore, John W.; Stanitski, Conrad L.

Published by Cengage Learning

ISBN 10: 1285199049

ISBN 13: 978-1-28519-904-7

Chapter 2 - Chemical Compounds - Problem Solving Practice 2.14 - Page 82: b

Answer

There are $0.0759$ moles of $KMnO_4$ in 12.0 g.

Work Step by Step

Calculate the molar mass for $KMnO_4$: 39.1* 1 + 54.94* 1 + 16.00* 4 = 158.04g/mol Find the number of moles in 12.0g: $12.0g \times \frac{1 mole}{158.04g} = 0.0759$ moles.

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