Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 2 - Chemical Compounds - Problem Solving Practice 2.14 - Page 82: a

Answer

There are $0.0731$ moles of $Ca(NO_3)_2$.

Work Step by Step

Calculate the molar mass for $Ca(NO_3)_2:$ 40.08* 1 + 2 * ( 14.01* 1 + 16.00* 3 ) = 164.10g/mol Calculate the number of moles on $12.0g$: $12.0g \times \frac{1 mole}{164.10g} = 0.0731 moles$
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