Answer
$_{36}^{92}Kr$
Work Step by Step
U-235 reacts with a neutron to form Kr-92, Sb-141, and 3 neutrons.
$_{92}^{235}U + _{0}^{1}n → _{36}^{92}Kr + _{56}^{141}Sb + 3 \space _{0}^{1}n $
Chemistry: The Molecular Science (5th Edition)
by Moore, John W.; Stanitski, Conrad L.
Published by
Cengage Learning
ISBN 10:
1285199049
ISBN 13:
978-1-28519-904-7
Chapter 18 - Nuclear Chemistry - Questions for Review and Thought - Topical Questions - Page 817c: 55c
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