Answer
$_{41}^{101}Nb$
Work Step by Step
U-235 reacts with a neutron to form Nb-101, Sb-132, and 3 neutrons.
$_{92}^{235}U + _{0}^{1}n → _{41}^{101}Nb + _{51}^{132}Sb + 3 \space _{0}^{1}n $
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