Answer
$142.12\,kJ/mol$
Work Step by Step
$\Delta_{r}G^{\circ}=\Sigma n_{p}\Delta_{f}G^{\circ}(products)-\Sigma n_{r}\Delta _{f}G^{\circ}(reactants)$
$=[\Delta_{f}G^{\circ}(CO,g)+3\Delta_{f}G^{\circ}(H_{2},g)]-[\Delta_{f}G^{\circ}(CH_{4},g)+\Delta_{f}G^{\circ}(H_{2}O,g)]$
$=[(-137.168\,kJ/mol)+3(0)]-[(-50.72\,kJ/mol)+(-228.572\,kJ/mol)]$
$=142.12\,kJ/mol$