Answer
$3.7\times10^{8}$
Work Step by Step
$K_{p}=K_{c}(RT)^{\Delta n}$
$\implies K_{c}=\frac{K_{p}}{(RT)^{\Delta n}}=\frac{1.5\times10^{7}}{(0.08206\times298)^{(2-3)}}=3.7\times10^{8}$
Chemistry: The Molecular Science (5th Edition)
by Moore, John W.; Stanitski, Conrad L.
Published by
Cengage Learning
ISBN 10:
1285199049
ISBN 13:
978-1-28519-904-7
Chapter 16 - Thermodynamics: Directionality of Chemical Reactions - Questions for Review and Thought - More Challenging Questions - Page 737h: 118c
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