Answer
$$K_p = 6.9 \space atm^{-1}$$
Work Step by Step
1. $T(K) = 25 + 273 = 298$
2. $\Delta n = 1 - 2 = -1$
3. $$K_p = K_c \times RT^{\Delta n} = (1.7 \times 10^{2}) \times (0.0821 \space L \space atm \space mol^{-1} \space K^{-1} \times 298 \space K)^{-1}$$
$$K_p = 6.9 \space atm^{-1}$$
