Answer
$$K_p = 1.6 \times 10^{-3}$$
Work Step by Step
1. $T(K) = 25 + 273 = 298$
2. $\Delta n = 1 - 2 = -1$
3. $$K_p = K_c \times (RT)^{\Delta n} = K_c \times (RT)^0 = K_c \times 1 = K_c$$
$$K_p = K_c = 1.6 \times 10^{-3}$$
Chemistry: The Molecular Science (5th Edition)
by Moore, John W.; Stanitski, Conrad L.
Published by
Cengage Learning
ISBN 10:
1285199049
ISBN 13:
978-1-28519-904-7
Chapter 12 - Chemical Equilibrium - Exercise 12.5 - Relating K(c) and K(p) - Page 535: c
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