Answer
The rate will decrease to one-fourth of the original rate.
Work Step by Step
$Rate= k[A]^{2}$
When the concentration of A is halved,
New Rate=$ (\frac{1}{2})^{2}\times k[A]^{2}= \frac{1}{4}(k[A]^{2}).$
Chemistry: The Molecular Science (5th Edition)
by Moore, John W.; Stanitski, Conrad L.
Published by
Cengage Learning
ISBN 10:
1285199049
ISBN 13:
978-1-28519-904-7
Chapter 11 - Chemical Kinetics: Rates of Reactions - Questions for Review and Thought - Topical Questions - Page 523a: 19b
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